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證明sin(x) 對x微分 出現sin(x)/x 在x趨近0的極限 羅畢達 需要用到sin(x) 對x的微分
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物理人看世界
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1 year ago
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物理人看世界
物理人看世界
數學物理愛好者
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2023-08-07
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Vicious Circle
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迷因是個好東西
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