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求8-6i的平方根 假設(a+bi)²=8-6i 展開實虛部分離 化為極式再半角 8-6i = 8-6i+a(1+i²) =ai²-6i+(a+8) 看成i的多項式 完全平方 令判別式=0
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物理人看世界
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1 year ago
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物理人看世界
物理人看世界
數學物理愛好者
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2023-08-07
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Brain Map (three Grids)
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Tede Liu
Usage Count - 174
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